Find the domain of $\sqrt{x^2-9}$ – math.stackexchange.com
$$\sqrt{x^2-9}$$ I know that the domain of square root is greater than or
equal to zero. I solve for when $x^2-9<0$ and get $x^2<9$. Now I get
$x<-3$ and $x<3$. I know that the domain is …
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